Question

The ratio of energy required to remove an electron from the first three bohrs ornits of hydrogen is

Answer 1

Answer:

36:9:4

Explanation:

For first bohr orbit energy = -13.6 eV

For second bohr orbit energy= -13.6/4 eV

For third bohr orbit energy = -13.6/9 eV

        Taking the ratios = -13.6: -13.6/4: -13.6/9

                                     = 1: 1/4:1/9

     Now making the denominator equal (LCM=36) we get the ratios as

           36:9:4