Math, asked by saraswatikirtanmanda, 2 days ago

The ratio of equal and unequal sides of an isosceles triangle is 3: 5. If its perimeter is 110cm, then its area is?​

Answers

Answered by tennetiraj86
10

Area of the given triangle is 414.5 cm²

Given :-

The ratio of equal and unequal sides of an isosceles triangle is 3:5.

Its perimeter is 110cm.

To find :-

Area of the triangle .

Solution :-

Given that

The ratio of equal and unequal sides of an Isosceles triangle = 3:5

Let they be 3X cm and 5X cm

The length of equal sides = 3X cm each

The length of unequal side = 5X cm

We know that

The perimeter of an Isosceles triangle is 2a+b units

Where, a is the length of equal sides and b is the length of unequal side.

The perimeter of the Isosceles triangle

=> P = 2(3X)+5X cm

=> P = 6X+5X cm

=> P = 11X cm

According to the given problem

The perimeter of the triangle = 110 cm

Therefore, 11X = 110

=> X = 110/11

=> X = 10 cm

If X = 10 cm then 3X = 3(10) = 30 cm

If X = 10 cm then 5X = 5(10) = 50 cm

We have,

The lengths of the three sides of the triangle are 30 cm , 30 cm and 50 cm

We know that

Area of an Isosceles triangle

= (b/4)(4a²-b²) sq.units

We have , a = 30 cm and b = 50 cm

Area of the given triangle

=> A = (50/4)√[4(30²)-50²] cm²

=> A = (25/2)√[4×900-2500]

=> A = (25/2)√(3600-2500)

=> A = (25/2)√1100

=> A = (25×10/2) √11

=> A = (250/2)√11

=> A = 125√11 cm² or

=> A = 125× 3.316

=> A = 414.5 cm²

(or)

we have, a = 30 cm , b = 30 cm ,

c = 50 cm

P = 110 cm, S = P/2 = 110/2 = 55 cm

We know that

Area of a triangle by Heron's formula

A = √[S(S-a)(S-b)(S-c)] sq.units

=> A = √[55(55-30(55-30)(55-50)] cm²

=> A = √[55(25)(25)5]

=> A = √(25×25×25×11)

=> A = 25×5√11

=> A = 125√11 cm² or

=> A = 125× 3.316

=> A = 414.5 cm²

Answer :-

The area of the given Isosceles triangle is 12511 cm² or 414.5 cm²

Used formulae:-

The perimeter of an Isosceles triangle is 2a+b units

Area of an Isosceles triangle

= (b/4)√(4a²-b²) sq.units

  • Where, a is the length of equal sides and b is the length of unequal side.

Area of a triangle by Heron's formula

A = √[S(S-a)(S-b)(S-c)] sq.units

  • a,b,c are the sides of the triangle.
  • S = (a+b+c)/2 = P/2 units

11 = 3.316 ...

Answered by reshab2014
3

Answer:

Step-by-step explanation:

let the three sides be 3x,3x and 5x

therefore;

3x+3x+5x=110

11x=110

x=10

Hence the sides are30,30 ,50 cm

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