Physics, asked by Khushiranjj, 6 months ago

The ratio of escape velocity on the surface of the moon to orbital velocity on the earth is _______ (take Re=64*10^5 m) Rm=1.74*10^6m)..... fill in the blanks​

Answers

Answered by ambikasanjayd
0

Explanation:

The escape velocity is exactly √2 times greater, about 40%, than the orbital velocity.

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