Question

the ratio of Fe3+ and Fe2+ in Fe _0.9 S_1.0 is​

Answer 1

Explanation:

Fe3+= x and Fe2+=.93-x. Using charge balance: 3*x+2*(0.93-x) = 2*1. ( 1 for oxygen). x = .14. % of Fe3+= (.14/.93)* 100. =15%. This conversation is already

Answer 2

Explanation:

hey there is answer !!

In Fe0⋅9S1⋅0, suppose Fe atoms = 90, then S- atoms = 100. Out of 90 Fe atoms, if Fe3+ = x, then Fe2+ = 90 - x.

As Fe3+ forms Fe2S3, S-atoms combine with x atoms of Fe3+=32x=1⋅5 x

As Fe2+ forms FeS, S-atoms combine with 90 - x atoms of Fe2+=(90−x)

Total S-atoms = 1.5 x + (90 - x) =100 or x = 20 = Fe3+

Ratio Fe3+/Fe2+=2070 = 0.28