The ratio of force between two charges at 2 m from each other
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hope it helps u this is the answer
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Explanation:
Charge is conserved so
Q1+Q2=Q3+Q4
Q1 and Q2 are initial charges and Q3 and Q4 are charges after connecting them
Q3=Q4=Q ( they are identical )
So Q=
2
10+20
Q=15C
Ratio of forces =K(10)(20):K(15)(15)
8:9
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