The ratio of height of a right circular solid cylinder and length of radius of base is 3:1. If the Volume Of the cylinder is 1029π cubic cm, what will be the total surface area of the cylinder?
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Answer:
Given :-
- The ratio of hight of a right circular solid cylinder and length of radius of base is 3 : 1 . If the Volume Of the cylinder is 1029 π cubic cm.
Find out :-
- The total surface area of the cylinder.
Solution :-
Let,
⋆ Hight = 3x
⋆ Radius of base = x
Volume =
★ πx² × 3x = 1029 π
➪ 3x³ = 1029
➪ x³ = 1029/3
➪ x³ = 343
➪ x = 7
⋆ Radius of base = 7 cm.
⋆ Hight = 21 cm.
Total surface area =
★ 2 × area of base + area of lateral surface
➭ 2 × πr² + 2πrh
➭ 2πr² + 2πrh
➭ 2πr(r + h)
➭ 2 × 22/7 × 7(7 + 21) sq cm.
➭ 44/7 × 7(28) sq cm.
➭ 44 × 28 sq cm.
➭ 1232 sq cm.
∴ The total surface area of the cylinder 1232 sq cm
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