The ratio of height of a tower and its shadow is 1 is to 1 then the angle of elevation is
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![\tan(x) = height \div shadow \\ tan(x) = 1 \div 1 \\ the \: function \: of \: tan \: is \: 1 \: at \: 45 \: \tan(x) = height \div shadow \\ tan(x) = 1 \div 1 \\ the \: function \: of \: tan \: is \: 1 \: at \: 45 \:](https://tex.z-dn.net/?f=+%5Ctan%28x%29++%3D+height+%5Cdiv+shadow+%5C%5C+tan%28x%29+%3D+1+%5Cdiv+1+%5C%5C+the+%5C%3A+function+%5C%3A+of+%5C%3A+tan+%5C%3A+is+%5C%3A+1+%5C%3A+at+%5C%3A+45+%5C%3A+)
therefore x=45°
therefore x=45°
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