The ratio of hydrogen and oxygen liberated at cathode and anode is 2:1 by volume. Why?
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The ratio of hydrogen and oxygen liberated at cathode and anode is 2:1 by volume because in a mole of water, there are 2 molecules of hydrogen and 1 molecule of oxygen.
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It is because
in 1 mole of water their is 2 molecules of hydrogen and 1 molecule is of oxygen.
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