The ratio of incomes of two friends is 8: 5 and the ratio of their expenditures is 3:2. If each of them manages
to save 1000 per month, then represent this situation algebraically.
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Given :- The ratio of incomes of two friends is 8: 5 and the ratio of their expenditures is 3:2. If each of them manages to save 1000 per month, then represent this situation algebraically. ?
Answer :-
Let us assume that,
- Income of friends = 8x and 5x .
- Expenditure of friends = 3y and 2y .
so,
→ saving = Income - Expenditure .
since both saves 1000 per month .
then,
→ 8x - 3y = 1000
→ 5x - 2y = 1000 .
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