The ratio of incomes of two persons is 9 : 7 and the ratio of their
expenditures is 4 : 3. If each of them manages to save 2000 per month, find their
monthly incomes.
Solution
I et us denote the incomes of the two person by 9x and * 7x and their why this is possible
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Given :-
The ratio of incomes of two persons is 9 : 7 and the ratio of their expenditures is 4 : 3. If each of them manages to save 2000 per month.
To find :-
Find their monthly incomes.
Solution :-
- The ratio of incomes of two persons = 9 : 7
- The ratio of their expenditures = 4 : 3
- Each of them manages to save = 2000
Let the income of two persons be 9x and 7x
- Expenditure of two persons be 4y and 3y
According to the given condition
- 9x - 4y = 2000 ----(i)
- 7x - 3y = 2000 -----(ii)
Multiply (i) by 3 and (ii) by 4
- 27x - 12y = 6000
- 28x - 12y = 8000
Subtract both the equations
→ 27x - 12y - (28x - 12y) = 6000 - 8000
→ 27x - 12y - 28x + 12y = - 2000
→ - x = - 2000
→ x = 2000
Put the value of x in equation (ii)
→ 7x - 3y = 2000
→ 7 × 2000 - 3y = 2000
→ 14000 - 3y = 2000
→ 14000 - 2000 = 3y
→ 12000 = 3y
→ y = 12000/3
→ y = 4000
Hence,
- Monthly income of two persons = 9x and 7x = Rs.18000 and Rs.14000
- Expenditure of two persons = 4y and 3y = Rs.16000 and Rs.12000
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Question
The ratio of incomes of two persons is 9 : 7 and the ratio of their expenditures is 4 : 3. If each of them manages to save 2000 per month. Find their monthly incomes.
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