the ratio of incomes of two persons is 9:7 and the ratio of their expenditures is 4:3. If each of them saves Rs 200 per month, find their monthly incomes.
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Answered by
10
Let the incomes per month of both the persons be Rs x and Rs y respectively.
Therefore
x/y = 9/7
=>7x-9y =0....(1)
As each person saves Rs 200 /month, the ratio of their expenditure will be (x-200):(y-200)
By the problem
x-200/y-200= 4/3
=>3x - 600= 4y-800
=>3x - 4y = - 200....(2)
On solving equation 1 and 2 simultaneously, we get,
y = 1400
Therefore, 7x - 9(1400)= 0
=>x =1800
The monthly income of both the persons is
Rs. 1400 and Rs. 1800 respectively.
Therefore
x/y = 9/7
=>7x-9y =0....(1)
As each person saves Rs 200 /month, the ratio of their expenditure will be (x-200):(y-200)
By the problem
x-200/y-200= 4/3
=>3x - 600= 4y-800
=>3x - 4y = - 200....(2)
On solving equation 1 and 2 simultaneously, we get,
y = 1400
Therefore, 7x - 9(1400)= 0
=>x =1800
The monthly income of both the persons is
Rs. 1400 and Rs. 1800 respectively.
rohanjeruel10:
equation (2) will be 3x-4y = -200
yes . sorry typing error
Answered by
1
Let the incomes per month of both the persons be Rs x and Rs y respectively.
Therefore
x/y = 9/7
=>7x-9y =0....(1)
As each person saves Rs 200 /month, the ratio of their expenditure will be (x-200):(y-200)
By the problem
x-200/y-200= 4/3
=>3x - 600= 4y-800
=>3x - 4y = - 200....(2)
On solving equation 1 and 2 simultaneously, we get,
y = 1400
Therefore, 7x - 9(1400)= 0
=>x =1800
The monthly income of both the persons is
Rs. 1400 and Rs. 1800 respectively.
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