Question

the ratio of K.E to P.E

Answer 1

-ratio of kinatic energy is - 2 and ratio of potential energy is 1

Answer 2

k.e. of the satellite=1/2*m*v^2
p.e. of satellite=-GmM/r (Formula for potential energy of a body placed near earth
or for the earth-satellite system)
Since the centrifugal force actin' on the satellite is provided by the gravitational force=
mv^2/r=GmM/r^2
v^2=GM/r
Therefore k.e.=GmM/2r
Ratio becomes=-1/2=-0.5
m-mass of satellite
M-mass of earth
r-distance of satellite from earth's centre
v velocity of satellite

Hope this will help you..... ✌