Question

the ratio of kinetic energy and potential energy of the electron in the bohr orbit of hydrogen atom is

Answer 1

According to Bohr's theory, the formula for calculating the Potential Energy of Hydrogen like species is −27.2(z2/n2)eV−27.2(z2/n2)eV

where z is the atomic number and n is the shell number.

For first shell of hydrogen atom put n=1 and z=1. You will get PE=−27.2eVPE=−27.2eV

PS PE is twice of KE (which has positive sign) in magnitude.

Answer 2

Answer: -1/2 .

Explanation:

Kinetic energy : 13.6 × Z²/n².

Where Z is atomic number and n is number of orbital or shell.

For hydrogen, Z (atomic number) = 1.

Then, kinetic energy is 13.6/n².

Now, potential energy = (-2) × 13.6 × Z²/n².

For hydrogen, potential energy = (-2) × 13.6/n².

Ratio = kinetic energy / potential energy = [13.6/ n²] / [-2× 13.6/n²] = 1/(-2) = 1 : -2.

Hope this helps...

Cheers.