the ratio of kinetic energy od two bodies is 2:1 and their momentum are in the ratio 1:2.the ratio of their masses is
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Let the masses of two bodies be m and M and the velocities be v and V respectively.
Given,
1/2MV² : 1/2mv² = 2:1. ———>1
MV : mv = 1:2. ———>2
Putting equation 2 in 1,
1/2 × 1 × V² : 1/2 × 2 × v² = 2:1
=>V² : v² = 4:1 ———>3
Putting equation 3 in 1,
1/2 × M × 2 : 1/2 × m × 1 = 2:1
=>M : m = 8 : 1.
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Given,
1/2MV² : 1/2mv² = 2:1. ———>1
MV : mv = 1:2. ———>2
Putting equation 2 in 1,
1/2 × 1 × V² : 1/2 × 2 × v² = 2:1
=>V² : v² = 4:1 ———>3
Putting equation 3 in 1,
1/2 × M × 2 : 1/2 × m × 1 = 2:1
=>M : m = 8 : 1.
Hope this will help you.
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Please mark it as brainliest
And
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Answered by
27
Hi mate!!!
K.E = p² / 2m
K.E)1 = 1 / 2m1....... equation 1
K.E)2 = 4 / 2m2...... equation 2
K.E)1 / K.E)2 = 2:1
On diving both the equations we get
2 :1 = (1/2m1 ) / (2/ m2)
m1 : m2 = 1:8
Have a nice time
K.E = p² / 2m
K.E)1 = 1 / 2m1....... equation 1
K.E)2 = 4 / 2m2...... equation 2
K.E)1 / K.E)2 = 2:1
On diving both the equations we get
2 :1 = (1/2m1 ) / (2/ m2)
m1 : m2 = 1:8
Have a nice time
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