Question

the ratio of kinetic energy values of 4g of hydrogen to 7g of nitrogen at room temperature is

Answer 1

Answer:

12.1

Explanation:

this the answer

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Answer 2

Answer:

The ratio of the kinetic energy of hydrogen to nitrogen at room temperature is 8:1.

Explanation:

The kinetic energy of gases is given as,

$K=\frac{3}{2}nRT$       (1)

Where,

K=kinetic energy of the gas

n=number of moles of the gas

R=universal gas constant

T=temperature of gas in kelvin

First, we need to find the number of moles of Hydrogen and Nitrogen

$n=\frac{m}{M}$                 (2)

Where,

m=given mass of the gas

M=molar mass of the gas

Number of moles of Hydrogen,

$n_1=\frac{4}{2}=2$                   (3)

Number of moles of Nitrogen,

$n_2=\frac{7}{28}=\frac{1}{4}$                (4)

K₁ =kinetic energy of Hydrogen

K₂ = the kinetic energy of Nitrogen

Now as per the question,

$\frac{K_1}{K_2}=\frac{\frac{3}{2}n_1RT}{\frac{3}{2}n_2RT}=\frac{n_1}{n_2}$       (5)

By substituting the required values in equation (5) we get;

$\frac{K_1}{K_2}=\frac{2}{\frac{1}{4}}=\frac{2\times 4}{1}=\frac{8}{1}$

Hence, the ratio of the kinetic energy of hydrogen to nitrogen at room temperature is 8:1.