Question

The ratio of latent heat of steam to latent heat of ice is

Answer 1

Answer:

Explanation:

Latent heat of steam =540 cal/g/°C

Latent heat of Ice = 80 cal/g/°C

Ratio = 540/80 = 27/8

Answer 2

1g of steam at 100∘C and an equal mass of ice at 0∘C are mixed. The temperature of the mixture in steady state will be : (latent heat of steam =540cal/g, latent heat of ice =80cal/g, specific heat of water =1cal/g∘C).

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