Question

the ratio of length and breadth of a rectangle is 3:2 and its perimeter is 160m. Find the area of rectangle?​

Answer 1

Answer:

let the length and breadth be 3x and 2x respectively. Now the equation is

perimeter= 2(l+b)

160/2 = (3x+2x)

80=5x

x = 80 /5

which is = 16.

Therefore length is 48 and breadth is 32.

now area = (l × b)

that is 48 × 16 = 768m2

Answer 2

Question:-

the ratio of length and breadth of a rectangle is 3:2 and its perimeter is 160m. Find the area of rectangle?

Answer:-

• The area of rectangle is 1536 m².

Solution:-

• Ratio = 3:2

Put x in the ratio

• Length = 3x
• Breadth = 2x
• Perimeter = 160 m

$\pink{ \mathfrak{ \underline{ \underline{ \green{ \huge{perimeter = 2(l + b)}}}}}}$

$\large{ \tt : \implies \: \: \: \:2(3x + 2x) = 160}$

$\large{ \tt : \implies \: \: \: \:5x = \frac{160}{2} }$

$\large{ \tt : \implies \: \: \: \:5x = 80}$

$\large{ \tt : \implies \: \: \: \:x = \frac{80}{5} }$

$\large{ \tt : \implies \: \: \: \:x = 16}$

• The value of x is 16 m.

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• Length = 3x = 3×16 = 48 m
• Breadth = 2x = 2×16 = 32 m

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$\pink{ \mathfrak{ \underline{ \underline{ \huge{ \blue{area = l \times b}}}}}}$

$\large{ \tt : \implies \: \: \: \:area = 48 \times 32}$

$\large{ \tt : \implies \: \: \: \:area = 1536 \: {m}^{2} }$

• The area of rectangle is 1536 m².