Question

The ratio of length and breadth of a rectangular
garden is 4:3. If its area is 4800 m’, find the cost of
fencing it with wire four times at the rate of
1.75 per m.​

Answer 1

AnswEr :

• Length : Breadth = 4 : 3
• Area of Garden = 4800 m²
• Rate of Fencing = Rs. 1.75 @m
• Find Cost of Fencing four times the garden.

Let the Length be 4x and, Breadth be 3x.

⋆ Refrence of Image is in the Diagram :

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• According to the Question Now :

$\longrightarrow \tt Area \:of \:Garden = 4800\:{m}^{2} \\ \\\longrightarrow \tt Length \times Breadth = 4800 \:{m}^{2} \\ \\\longrightarrow \tt4x \times 3x = 4800 \\ \\\longrightarrow \tt12 {x}^{2} = 4800 \\ \\\longrightarrow \tt {x}^{2} = \cancel\dfrac{4800}{12} \\ \\\longrightarrow \tt {x}^{2} = 400 \\ \\\longrightarrow \tt x = \sqrt{400} \\ \\\longrightarrow \tt x = \sqrt{20 \times 20} \\ \\\longrightarrow \blue{ \tt x = 20}$

$\rule{300}{1}$

• D I M E N S I O N S :

◗ Length = 4x = 4(20) = 80 m

◗ Breadth = 3x = 3(20) = 60 m

$\rule{300}{2}$

• Cost of Fencing of Rectangluar Garden :

↠ Cost = Times × Perimeter × Rate

↠ Cost = 4 × 2(L + B) × Rate

↠ Cost = 4 × 2(80 + 60) × 1.75

↠ Cost = 4 × 2 × 140 × 1.75

↠ Cost = Rs. 1960

⠀

∴ Cost of Fencing of Garden is Rs. 1960

$\rule{300}{3}$

$\star \: \underline \text{Some \:Information \:about \:Rectangle :}$

⋆ Opposite sides are equal and parallel.

⋆ All angles are equal to 90 degrees.

⋆ The diagonals are equal and bisect each other.

⋆ The intersection of the diagonals is the circumcentre. That is you can draw a circle with that as centre to pass through the four corners.

⋆ Any two adjacent angles add up to 180 degrees.

⋆ Lines joining the mid points of the sides of a rectangle in an order form a rhombus of half the area of the rectangle.

⋆ The sum of the four exterior angles is 4 right angles.

⋆ Area of Rectangle = Length * Breadth

⋆ Perimeter of Rectangle = 2*(Length + Breadth)

#answerwithquality #BAL

Answer 2

${\large\bf{\mid{\overline{\underline{Given:-}}}\mid}}$

• Length : Breadth = 4:3
• Area = 4800m²
• Cost of fencing = 1.75 per metre .

$\Large\bold\star\underline{\underline\textbf{Formula\:used}}$

• Area of Rectangle = length * Breadth
• Fencing is done outside all Four sides , that means perimeter of Rectangle = 2(length + Breadth) .
• Cost of Fencing = Total perimeter * Rate per metre .

$\large\star{\underline{\tt{\red{Answer}}}}\star$

Let Length and Breadth of Rectangle be 4x and 3x .

Area of Rectangle is given = 4800m²

so,

→ 4x * 3x = 4800

→ 12x² = 4800

dividing both sides by 12 we get,

→ x² = 400

Square root both sides now , we get,

→ x = √20*20 = 20m .

Hence, Length of rectangle = 4*20 = 80m

Breadth = 3*20 = 60m.

Now,

Perimeter of Rectangle = 2(l+b) = 2(80+60) = 280m.

But , it has been said that Fencing was done 4 times .

so, Total length of wire Required = 280*4 = 1120m.

Now, cost of Fencing the wire = 1120*1.75 = Rs.1960.

Hence, Total cost of Fencing the wire Four times will be Rs.1960...

__________________________________

$\large\bold\star\underline\mathcal{Extra\:Brainly\:Knowledge:-}$

1) Each of the interior angles of a rectangle is 90°.

2) The diagonals of a rectangle bisect each other.

3) The opposite sides of a rectangle are parallel.

4) The opposite sides of a rectangle are equal.

5) A rectangle whose side lengths are a and b has area = a×b×sin90° = a×b

6) A rectangle whose side lengths are a a and b b has perimeter 2(a + b)...

7) The length of each diagonal of a rectangle whose side lengths are a and b is √(a²+b²) ..

#BAL

#answerwithquality..