The ratio of length and breadth of a rectangular plot is 7 : 4. The cost of fencing this field at the rate of Rs. 75 per meter is Rs. 16,500. Find the dimensions of the plot.
Answers
Step-by-step explanation:
Length is 140 m and breadth is 80 m. Hope it helps
Answer :
40 m
Explanation:
given the ratio between the Length and the breadth of the rectangular field is 7 : 4
given the ratio between the Length and the breadth of the rectangular field is 7 : 4let the length and breadth of the rectangular field be 7x and 4x respectively.
given the ratio between the Length and the breadth of the rectangular field is 7 : 4let the length and breadth of the rectangular field be 7x and 4x respectively.ATQ, the cost of fencing the rectangular field @ 75 rupees per m is rupees 16500
•therefore perimeter of the rectangular field = 16500/75
therefore perimeter of the rectangular field = 16500/75= 220m
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11➡ x = 10m
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11➡ x = 10mhence,
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11➡ x = 10mhence,length of the rectangular field = 7x
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11➡ x = 10mhence,length of the rectangular field = 7x= 7 × 10
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11➡ x = 10mhence,length of the rectangular field = 7x= 7 × 10= 70m
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11➡ x = 10mhence,length of the rectangular field = 7x= 7 × 10= 70mbreadth of the rectangular field = 4x
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11➡ x = 10mhence,length of the rectangular field = 7x= 7 × 10= 70mbreadth of the rectangular field = 4x= 4 × 10
therefore perimeter of the rectangular field = 16500/75= 220mformula for the perimeter of a rectangle is 2(l + b)➡ 2(l + b) = 220m➡ 2(7x + 4x) = 220m➡ 7x + 4x = 220/2➡ 11x = 110m➡ x = 110/11➡ x = 10mhence,length of the rectangular field = 7x= 7 × 10= 70mbreadth of the rectangular field = 4x= 4 × 10= 40m
hope it will help u