The ratio of length and breadth of rectangle is 3:2 and its perimeter is 100m . Lets find the area of rectangle.
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Answered by
10
Heya
Perimeter of rectangle = 100m
ratio of length is to breadth = 3:2 = 3x : 2x
Perimeter = 2(l+b)
P = 2(3x+2x)
= 6x + 4x = 10x
10x = 100 ; x = 100/10 = 10
l = 3x = 3 × 10 = 30 m
b = 2x = 2 × 10 = 20 m
Area of rectangle = length × breadth ( l×b )
A = 30 × 20 = 600 sq.m
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THANKS
Perimeter of rectangle = 100m
ratio of length is to breadth = 3:2 = 3x : 2x
Perimeter = 2(l+b)
P = 2(3x+2x)
= 6x + 4x = 10x
10x = 100 ; x = 100/10 = 10
l = 3x = 3 × 10 = 30 m
b = 2x = 2 × 10 = 20 m
Area of rectangle = length × breadth ( l×b )
A = 30 × 20 = 600 sq.m
=======================================================
THANKS
Answered by
2
Let the length And breadth be 3x and 2x
Therefore,
2(3x+2x)=100
5x=100/2
5x=50
x=50/5
x=10
Length=3x=3×10=30 m
Breadth=2x=2×10=20 m
Area=length× breadth
=30×20=600 m^2 (ans)
Therefore,
2(3x+2x)=100
5x=100/2
5x=50
x=50/5
x=10
Length=3x=3×10=30 m
Breadth=2x=2×10=20 m
Area=length× breadth
=30×20=600 m^2 (ans)
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