Question

The ratio of length and breadth of the park is 61:51.The area of the park is 12444 square meters.Find the perimeter of the park?

Answer 1

let the length =61x
let the breadth = 51x
area = l×b
12444=61x × 51x
12444=3111x^2
1244÷311=x^2
4=x^2
√4=x
x=2
length = 61 ×2
122m
breadth =51×2
102m
Perimeter=2(l+b)
p=2(122+102)
p=2×224
p=448m Ans

Answer 2

Given, the ratio of the length and breadth of the park is = 61:51
Area of the park is =12444m^2
perimeter of the park is = ?
Area is = 12444
l×b = 12444
61x×51x=12444
3111x^2 = 12444
x^2= 12444/3111
x^2=4
x=2
therefore length and breadth are 122 and 102
then perimeter is = 2(l+b)
= 2(122+102)
= 2(224)
=448m
therefore perimeter of park is 448m