Question

The ratio of length breadth and height of a big room is 5:3:2 and its total surface area is 1550M SQUARE find the dimensions of the room aslo find the cost of white washing the four walls of and ceiling of the room at the rate of rupees 6.95 per meter square

Answer 1

Answer:

Step-by-step explanation: Let l= 5x, b= 3x and h=2x,

TSA= 2lb+2bh+2hl = 1550

         2(5x)(3x) + 2(3x)(2x) + 2(2x)(5x) = 1550

         30x^{2} + 12x^{2} + 20x^{2} = 1550

         62x^{2} = 1550

         x^{2} = \frac{1550}{62}

         x^{2}= 25

         x = 5 m

∴ l = 25 m, b=15 m and h= 10m

Area to be white washed = LSA + lb

                                            = 2(l+b)h + 25*15

                                            = 2 (40) 10 + 375 m^{2}

                                            = 800 + 375 = 1175 m^{2}

Cost of white washing 1 m^{2}  of wall = 6.95 rupees

cost of white washing 1175 m^{2} of wall = 1175 * 6.95 = 8166.25 rupees