Question

the ratio of lengths of parllel of a trapezium is 2:5 the distance between them is 10cm. area of trapezium is 720cm, find the lenghts of parllel sides

Answer 1

GIVEN :

† Ratio of length of parallel sides of a trapezium is 2:5. Distance between them is 10 cm. If the area of trapezium is 720cm²

TO FIND :

† Length of parallel sides

Solution :

★ Ratio of length of parallel sides = 2 : 5

★ Distance between parallel sides = 10 cm

★ Area of trapezium = 720 cm²

Let the parallel sides be 2x and 3x

$\\{\underline{\boxed{\bf{\red{Area\:of\:trapezium=\dfrac{1}{2}\times{(a+b)}\times{h}}}}}}$

$:\implies\sf 720 = \dfrac{1}{2}\times{(2x+5x)}\times{10}$

$:\implies\sf 720=\dfrac{1}{2}\times{7x}\times{10}$

$:\implies\sf 720=5\times{8x}$

$:\implies\sf \dfrac{720}{5}=8x$

$:\implies\sf 144=8x$

$:\implies\sf x=\cancel\dfrac{114}{8}$

$:\implies\sf x=18cm$

Length of parallel sides :

Length of the first parallel side = 2x = 2 × 18 = 36 cm

Length of the second parallel side = 5x = 5 × 18 = 90 cm

Answer 2

Answer:

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