The ratio of lengths of two rods of different materials is taken as 2 : 3 such that the difference of their lengths is 10 cm at all temperatures. The length of the rod of lesser expansion is a x 10 cm. The value of a is
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Explanation:
since the difference in length for both the rods are same always, we can write,
α
1
l
1
=α
2
l
2
l
1
/l
2
=α
2
/α
1
or, (l
1
−l
2
)/l
2
=(α
2
−α
1
)/α
1
= 0.55/1.1 = 1/2
(l
1
−l
2
) = 10 (given)
Calculating we ge l
1
= 30 cm . So, l
2
= 20 cm
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