Question

The ratio of lone pairs on the surrounding atoms to that of central atom of xeo2f2 is

Answer 1

Answer:

10:1

Explanation:

refer to the image attached

Answer 2

Answer:

4:1

Explanation:

XeOF2  has four bond pairs of electrons and a couple of lone pairs of electrons.

Hence, the ratio of bond pair-lone pair electrons  is two.

In Xenon Dioxide Difluoride, xenon might be the principal atom with the intention to have eight valence electrons. The fluorine atom might be the monovalent surrounding atom and the oxygen atom might be the divalent surrounding atom. We will take the 8 valence electrons of Xenon and upload 2 monovalent fluorine atoms. The entire sum might be divided via way of means of 2 on the end.

If we take the values then;

Number of electrons = ½ [8+2-0+0]

= five

We get five because the very last quantity which similarly indicates sp3d hybridization. In Xenon Dioxide Difluoride, there might be five sp3d hybrid orbitals. There are five electron pairs across the centre atom wherein it's going to comprise four bond pairs and 1 lone pair.

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