Question

The ratio of magnetic field at the centre of current carrying coil of radius a and at distance a frim the centre of the coil and perpendicular to the axis of the coil is

Answer 1

Three steps solutions

Explanation:

Magnetic field at centre is inversely proportional to the radius 'a' and the magnetic field at a distance is proportional to

$\frac{a^2}{(a^ 2+ r^2)^\frac{3}{2}}$

Where,

r = Perpendicular distance from centre

Now as r = a solving it gives 2√2