Question

the ratio of magnitude of displacement to the distance travelled by the particle which covers a semicircular arc of radius R is​

Answer 1

Answer:

2/π

Explanation:

the distance travelled by a particle on semicircular arc is

πR

because the arc of circle is 2πR

so the arc of semicircle is 2πR/2=πR

the displacement travelled by a particle on semicircular arc is

2R

so the ratio of displacement and distance is

2R = 2

πR π

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Answer 2

Answer:

The ratio of the magnitude of displacement to the distance traveled by the particle is $\frac{2}{\pi }$.

Explanation:

We have the distance traveled by the particle on a semicircular arc is $\pi r$ as the arc of the circle is $2\pi r$.

As displacement is the shortest distance traveled which is the diameter of the semicircle.

Hence, displacement $=2r$

Therefore, the ratio of the magnitude of displacement to the distance traveled by the particle is:

$\frac{2r}{\pi r}=\frac{2}{\pi }$ .

The ratio of the magnitude of displacement to the distance traveled by the particle which covers a semicircular arc of a radius $r$ is $\frac{2}{\pi }$.

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