Question

The ratio of males to females in a committee of 48 members is 3:1. How many more ladies be added to the committee so that the ratio of males to females may be 9:5 ​

Answer 1

Answer:

8

Solution:

Here,

It is given that ,

The ratio of males to females in a committee of 48 members is 3:1.

Thus,

Let the no. of males = 3x

And the no. of females = x

According to the question ;

=> 3x + x = 48

=> 4x = 48

=> x = 48/4

=> x = 12

Thus,

No. of males = 3x = 3•12 = 36

No. of females = x = 12

Now,

Let the no. of more ladies to be added be y , so that the ratio become 9:5.

Thus,

=> 36:(12 + y) = 9:5

=> 36/(12 + y) = 9/5

=> 36•5 = 9•(12 + y)

=> 12 + y = 36•5/9

=> 12 + y = 20

=> y = 20 - 12

=> y = 8

Hence,

The required answer is 8 .

Answer 2

Answer:

• 8 females.

Step-by-step explanation:

Given

• Ratio of males to females = 3 : 1
• Number of members in a committee = 48

To find

• How many more ladies be added to the committee so that the ratio of males to females becomes 9 : 5.

Solution

Total numbers of members in a committee = 48

Ratio of males to females = 3 : 1

Sum of terms of ratio = 3 + 1 = 4

Number of males = 3/4 × 48

Number of males = 36.

Number of females = (48 - 36) = 12.

Let x be the number of females be added to the committee.

Then, number of females = 12 + x

ATP:

• 36/(12 + x) = 9/5
• 9(12 + x) = 180
• 9x = (180 - 108)
• 9x = 72
• x = 72/9
• x = 8

Hence, more 8 ladies must be added to the committee so that the ratio of males to females will be 9 : 5.