The ratio of mass percent of C and H of an organic compound
(CxHyOz) is 6:1. If one molecule of the above compound (CxHyOz)
contains half as much oxygen as required to burn one molecule of
compound CxHy completely to CO2 and H20. The empirical formula of
compound CxHyOz is : (a) C2H4O; (b) C3H6O3 (c) C2H40 (d) C2H4O2
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Answer:
C2H4O3
Explanation:
Mistake in options:
Option A and C are same
One must be C2H4O3
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