Question

The ratio of mass percent of c and h of an organic compound (cxhyoz) is 6 : 1. If one molecule of the above compound (cxhyoz) contains half as much oxygen as required to burn one molecule of compound cxhy completely to co2 and h2o. The empirical formula of compound cxhyoz is :

Answer 1

Mass ratio of C & H is 6 :

So mole ratio of C & H is 1 : 2

\therefore X : Y = 1 : 2

To burn one molecule of C_{X}H_{Y}

CH_{2}+\frac{3}{2}O_{2}\rightarrow CO_{2}+H_{2}O

\frac{3}{2} molecule of O_{2} is required i.e. 3 atoms of O are required so X:Y:Z= 1:2:\frac{3}{2}\Rightarrow X:Y:Z= 2:3:4

So empirical formula is C_{2}H_{4}O_{3}

Option 1)

C2H4O3

Option 2)

C3H6O3

Option 3)

C2H4O

Option 4)

C3H4O2

Answer 2

Answer:

C2H4O3

Hope it helps.....