Question

the ratio of maximum height achieved and range of a projectile with 50 m/s at an angle 45° is

a. 1:1
b. 1:2
c. 2:1
d. 1:4 ​

Answer 1

Explanation:

1) For (45+a)

Range =

g

u

2

sin(2a)

Range(1)=

g

u

2

sin(2×(45+a))

=

g

u

2

cos2a

2) For (45−a)

Range(2)=

g

u

2

sin(90−2a)

=

g

u

2

cos2a

Range(2)

Range(1)

=

1

1

=1:1