The ratio of maximum height reached to maximum horizontal range of a projectile depends upon
a) sin α
b) Cos α
c) sin2 α
d) cos2α
Answers
Answered by
0
ratio of max height to horizontal range is
depends upon sin2alpha
as it is in denominator in 1st step
Attachments:
Answered by
0
Concept:
- Projectile motion
- The maximum height of a projectile
- The maximum horizontal range of a projectile
Given:
- The maximum height of a projectile H = u^2sin^2 θ/2g
- The maximum horizontal range of a projectile R = u^2 sin 2θ/g
Find:
- The ratio of maximum height to the maximum horizontal range of a projectile
Solution:
H/R = (u^2sin^2 θ/2g) / (u^2 sin 2θ/g)
H/R = (sin^2 θ/2g) / (sin 2θ/g)
H/R = (sin^2 θ/2) / (sin 2θ)
H/R = (sin^2 θ) / (2 sin 2θ)
H/R = sin^2 θ/ 2 (2 sinθ cos θ)
H/R = sin θ/4 cos θ
The correct option is both a and b.
#SPJ3
Similar questions