Question

the ratio of meas of side of triangle is 3:4:5. if semiperimeter of the triangle is 36 cm the measure of longest side is ? cm​

Answer 1

Semi perimeter=36

so total perimeter=36+36=72

side a=3x

side b=4x

side c=5x

Therefore total perimeter=3x+4x+5x

3x+4x+5x=72

12x=72

x=72/12

x=6

Therefore measure of the longest side=5×6=30cm

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Answer 2

Answer:

THE MEASURE OF THE LONGEST SIDE IS 30 CM

Step-by-step explanation:

LET ABC BE THE TRIANGLE HAVING RATIO OF ITS SIDE 3:4:5

THEREFORE AB,BC AND AD ARE THE SIDES OF THE TRIANGLE AND LET THEIR MEASURES BE 3X , 4X AND 5X RESPECTIVELY.

SEMIPERIMETER OF A TRIANGLE IS HALF THE PERIMERTER OF TRIANGLE.

SEMIPERIMETER OF TRIANGLE ABC =

SUM  OF THE SIDES OF TRIANGLE ABC/2

36 = 3X+4X+5X/2

36 = 12X/2

36 = 6X

X= 36/6 = 6CM

THE LONGEST SIDE OF TRIANGLE ABC = 5X = 5*6 = 30CM