Question

The ratio of milk and water in a mixture of 78 litres is 8 : 5. If this ratio becomes 3: 4 on adding some water to the

mixture, then the quantity of the water further added is______

with explanation also , not only answer !!!​

Answer 1

Given :

Ratio of milk and water : 8:5

Total litres in the mixture : 78 litres

Ratio (after adding some water) : 3:4

To find :

The quantity of water added to the mixture.

Solution :

First, we should find the quantity of water and milk in that mixture originally.

$\sf \dashrightarrow 8 : 5 = 78$

$\sf \dashrightarrow 8x + 5x = 78$

$\sf \dashrightarrow 13x = 78$

$\sf \dashrightarrow x = \dfrac{78}{13}$

$\sf \dashrightarrow x = 6$

Original quantity of milk :

$\sf \dashrightarrow 8x = 8(6)$

$\sf \dashrightarrow 48 \: litres$

Original quantity of water :

$\sf \dashrightarrow 5x = 5(6)$

$\sf \dashrightarrow 30 \: litres$

Now, we can find the quantity of water added to the mixture.

More quantity of water added :

Let the extra amount of water added be y.

$\sf \dashrightarrow 48 : 38 + y = 3 : 4$

$\sf \dashrightarrow \dfrac{48}{38 + y} = \dfrac{3}{4}$

$\sf \dashrightarrow 3(38 + y) = 4(48)$

$\sf \dashrightarrow 114 + 3y = 192$

$\sf \dashrightarrow 3y = 192 - 114$

$\sf \dashrightarrow 3y = 78$

$\sf \dashrightarrow y = \dfrac{78}{3}$

$\sf \dashrightarrow y = 26$

Hence, 16 litres of water was added to the mixture, later.

Answer 2

Answer:

34

Step-by-step explanation:

M=milk

W=water

X=water further addition

3/4=milk/water+X

M=78×（8/8+5）

=78×（8/13）

=48

W=78×（5/8+5）

=78×（5/13）

=30

3/4=M/W+X

=48/30+X

30+X=48×4/3

=64

X=64-30

=34

Thus,the quality of the water further added is 34litres