Question

The ratio of molecules present in 44 g of co2 and 5.6 L (at stp) of so2 is

Answer 1

Answer:

Explanation:

no. of molecules=moles*avagadro number

lets calculate no . of moles in each

in case1

no. of moles

44/44

1

no. of moles

=1

therefore no. of molecules

1*avagadro number

=avagadro

in case2

moles=

for 1 mole we have 22.4

for x moles we have 5.6

x=0.25

therefore no. of molecules

=0.25*avagadro

ratio=

avagadro/0.25*avagadro

4