Question

The ratio of moment of inertia of disc and hoop ?​

Answer 1

Answer:

$\frac{I_d}{I_h} = \frac{1}{2}$

Explanation:

By considering the disc and the hoop of mass M and radius R we get:

Moment of inertia of disc  about an axis which is perpendicular to it and passing through its centre $(I_d) = \frac{MR^2}{2}$.

Moment of inertia of hoop  about an axis which is perpendicular to it and passing through its centre$(I_h)= MR^2$.

So, the ratio of moment of disc to the moment of hoop is $\frac{I_d}{I_h}= \frac{\frac{MR^2}{2} }{MR^2}$.

Therefore, $\frac{I_d}{I_h} = \frac{1}{2}$.

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