The ratio of moments of inertia of two solid spheres of same mass but densities in the ratio 1:8 is
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Answered by
33
Let M1 and M2 be the masses of two solid spheres of densities d1 and d2.
According to your problem , M1 = M2
M = 4/3πR³ X d
so , 4/3πR1³ X d1 = 4/3πR2³ X d2
= (R1/R2)³ = d1/d2 = 8/1
R1/R2 = 2/1.
The ratio of moments of inertia of the spheres ,
(R1/R2)² = (2/1)²
= 4/1
Answered by
20
Hey friend your answer is
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Assuming M1 and M2 the masses of solid spheres of densities D1 and D2
ACCORDING TO THE QUESTION,
M=4/3 πr³*d
Then,
4/3πr1³*d1
=4/3r2³*d²
=>{r1/r2)={d1/d2}
r1/r2 =2/1
Ratioof moments of inertia (r1/r2)²
=(2/1)²
=4/1
=4:1
•°•Your answer is 4:1
××××××××××××××××××××××××
Assuming M1 and M2 the masses of solid spheres of densities D1 and D2
ACCORDING TO THE QUESTION,
M=4/3 πr³*d
Then,
4/3πr1³*d1
=4/3r2³*d²
=>{r1/r2)={d1/d2}
r1/r2 =2/1
Ratioof moments of inertia (r1/r2)²
=(2/1)²
=4/1
=4:1
•°•Your answer is 4:1
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