The ratio of momentum of an electron and Alfa partical which are accelerated from rest by a potential difference 100V is
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Your answer is :-
Explanation:
Work done in accelerating a charge of magnitude q through a potential of V is qV
This work is converted into KE of charged particle.
The magnitude of charge on alpha particle is twice that of electron.
So,
KEα=2×KEe
2mαpα2=2×2mepe2
∴pαpe=2mαme
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