Question

The ratio of momentum of body A having mass "m" and velocity "v" to that body B having mass "2m" and velocity "2v" is??​

Answer 1

Answer:

1:4

Explanation:

momentum p= mv

let momentum of bodyA

Pa= mv

momentum of body B

Pb= 2m×2v

= 4mv

ratio of Pa to Pb

Pa/Pb = mv/4mv

= 1:4

Answer 2

The ratio of momentum of the body A to that body B is 1/4.

Explanation:

The momentum of a body is given as

p = mv

Here, m is the mass of the body and v is its velocity.

For the body A, the momentum

$p_{A}  = mv$

For the body B,  

$p_{B}  = 2m\times2v$

$p_{B}=4mv$   ( given for B, mass = 2m and velocity = 2v)

So, the ratio of momentum of the body A to that body B,

$\frac{p_{A}}{p_{B}} =\frac{mv}{4mv}$

$\frac{p_{A}}{p_{B}}=\frac{1}{4}$

Thus, the ratio is 1/4.

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Topic: Momentum

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