Question

The ratio of money in Brian's wallet to Colin's wallet one day was 7:2.
Brian spent £39 that day.
Brian now had £4 less than Colin.
How much did Colin initially have?

Answer 1

Given

$\bold{Amount \ in \ Brian's \ wallet} = 7x \\\bold{Amount \ in \ Colin's \ wallet} = 2x$

Brian spent £39 that day.

$\implies 7x - 39$

Brian now had £4 less than Colin.

$\implies 2x -4= 7x- 39 \\\implies 7x-2x=4+39 \\\implies 5x=35 \\\implies x = 7$

Amount in Brian's wallet  = 7(7)

                                            = £49

Amount in Colin's wallet = 2(7)

                                           = £14

The amount they had together =  £49+£14

                                                      = £63

$\boxed{\boxed{\bold{So , \ They \ had \ 63 \ pounds \ altogether \ initially. }}}}$

                                                     

Answer 2

Answer:

Given

\begin{lgathered}\bold{Amount \ in \ Brian's \ wallet} = 7x \\\bold{Amount \ in \ Colin's \ wallet} = 2x\end{lgathered}

Amount in Brian

′

s wallet=7x

Amount in Colin

′

s wallet=2x

Brian spent £39 that day.

\implies 7x - 39⟹7x−39

Brian now had £4 less than Colin.

\begin{lgathered}\implies 2x -4= 7x- 39 \\\implies 7x-2x=4+39 \\\implies 5x=35 \\\implies x = 7\end{lgathered}

⟹2x−4=7x−39

⟹7x−2x=4+39

⟹5x=35

⟹x=7

Amount in Brian's wallet = 7(7)

= £49

Amount in Colin's wallet = 2(7)

= £14

The amount they had together = £49+£14

=