Physics, asked by deerasLynpa, 1 year ago

The ratio of no of collisions per second at the walls of container by He and O2 gas molecules kept at same volume and temperature is ?

Answers

Answered by sawakkincsem
55

First we will define Collision Frequency, it is defined as the number of collisions which take place in 1 second among the molecules present in 1 cc of the gas. 


Also collision number (Nc) is the number of collisions which a single molecule undergoes with other molecules in 1 second. 


SNc 2πvo


Where v  = average speed  


O = molecular diameter 


N = number of molecules  


Collisions among molecules will be Nc * n 


Each collision requires 2 molecules, collision frequency  


Z = (Nc * n) / 2 = (½) * πvo2 n2  


Average speed (v) = sqrt(8RT/(πM)) where M is the molecular mass 


Hence, 


Z = 2o2nsqrt(πRTM) 


This is the required formula for this question 


We know that M for 0molecule is 32u and for Helium molecule is 4u 


Hence z1/z2 = ratio of He to that of Oxygen = (const/sqrt4) * (sqrt32/const) 


= sqrt(8/1) 


= 2 2 :1

Answered by shardulratnakar
22

Answer:

2√2:1

Explanation:

No.of collision is inversely proportional to√ molecular mass

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