Math, asked by krishna66113, 4 months ago

The ratio of number of active turns of a Plain end Grounded spring to square and spring having total no.of turns as 10.​

Answers

Answered by shubhamkh9560
6

Answer:

Commonly used ratios are C = 4 to 10. ... for plain ends p = ... n = 2 assuming squared and ground ends ... Find the no. of active turns required if the spring is made of 20 mm dia wire and.

Step-by-step explanation:

The ratio of number of active turns of a Plain

end Grounded spring to square and spring

having total of turns as 10.

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Answered by sourasghotekar123
0

Answer:

C = 4 to 10 is a commonly used ratio, and for plain ends, p =... n = 2 is assumed, assuming squared and ground ends... If the spring is made of 20 mm diameter wire, the number of active turns needed.

The proportion of a Plain end's active turns a spring that is square-grounded and has a total of 10 revolutions.

Step-by-step explanation:

On helical compression springs, there are fundamentally four (4) different sorts of ends: closed & ground, closed & not ground, open & ground, and open & not ground.

When the wire size is smaller than.020-inches and/or the spring index exceeds 12:1, a spring with closed ends and no ground is the easiest to make and frequently operates well.

Better seating (squareness), which affects how the axial force generated by the spring is communicated to its mating part or the mechanism it works in, is offered by closed and ground end springs. Closing and grinding the spring's ends helps to reduce buckleing.

When a lower solid height is required, this method is typically used to create open and ground springs.

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https://brainly.in/question/17249982

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