Question

the ratio of number of balls in bags x,y is 2:3 . five Balls are taken from bag y and are dropped in bag X. numbers of balls are equal in each bag now . numbers of balls in each bag now is ?​

Answer 1

Answer:

No. of balls 2 : 3

2x : 3x

=> now 5 balls are taken out of bag y and Put in bag x

2x+53x−5=11

=> 2x + 5 = 3x - 5

x = 10

No. of balls in each bag is

x=>2×10+5=25

y=>3×10−5=25

Step-by-step explanation:

hope it is clear

Answer 2

⇒ Given:

The ratio of number of balls in bags x and y is 2:3.

Five balls are taken from bag Y and dropped in X making the number of balls equal.

⇒ To Find:

The number of balls in each bag.

⇒ Solution:

That ratio of the balls in both the bags = 2:3.

Let the number of balls in each bag be 2x and 3x.

It is given that when 5 balls from Y is added to bag X, they become equal.

Forming an equation of the given statement:

$\sf{\dfrac{2x+5}{3x-5}=\dfrac{1}{1}}$

That is,

3x - 5 = 2x + 5

Moving the variables to the LHS and constants to the RHS:

3x - 2x = 5 + 5

x = 10

Therefore the number of balls in each bag now:

Bag X

= 2x + 5

= 2 x 10 + 5

= 20 + 5

= 25

Bag Y

= 3x - 5

= 3 x 10 - 5

= 30 - 5

= 25

Hence both the bags contain 25 balls each.

⇒ Verification:

It is said earlier that when five balls in bag Y are added to bag X, they become equal. Here, we got the answer as each bag has got 25 balls each.

Therefore, our answer is verified.