The ratio of number of males and number of females in village X is 11:7 respectively. If in village Y, the number of males is 20% more than the number of males in village X and the number of females is 12% less than those in village X, then what will be the respective ratio of males to females in village Y ?
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Answer:15/7
Step-by-step explanation:
Given in village X,
M/F=(11/7).........................(1)
And, in village Y,
(M+20%of M)/(F-12% of F)=M'/F'=?
From (1), 7M=11F
Or,M=(11/7)F
From (2), {M+(20/100)M}/{F-(12/100)F}=M'/F'
Or, {M+(M/5)} / {F-(3/25)F}=M'/F'
Or, (6M/5)/(22F/25)=M'/F'
Or, {6*(11/7)F/5} / {22F/25}=M'/F'
Or, {(66/35)F}/{22F/25}=M'/F'
Or, (66/35)×(25/22)=M'/F'
Or, (3×5)/7=M'/F'
Therefore, M'/F'=15/7
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