Question

The ratio of number of mole of AgNO3.
PbNO3)2 and Fe(NO3) required for coagulation
a a definite amount of colloidal solution of silver
iodide Prepaired by mixing AgNO3 with excess of
KI will be ​

Answer 1

The ratio of number of mole of AgNO₃, Pb(NO₃)₂ and Fe(NO₃)₃ required for coagulation of a definite amount of colloidal solution of silver iodide prepared by mixing AgNO₃ with excess of KI will be ​equal to 3:2:1

• The colloidal solution formed on mixing AgNO₃ with excess of KI will be negatively charged.
• Hence, the cations will be used to coagulate the colloidal solution.
• According to Schulz's rule, the number of moles of a substance required to coagulate a colloidal solution is inversely proportional to the charge possessed by the ion used for coagulation.
• The cations are Ag⁺, Pb²⁺ and Fe³⁺, hence the ratio of the moes required will be 3:2:1