Question

The ratio of peak value and r.m.s value of an alternating current is
(a) 1
(b) $\frac{1}{2}$
(c) √2
(d) 1/√2

Answer 1

answer : option (d) $\frac{1}{\sqrt{2}}$

explanation : we know an important formula
$\quad\boxed{\bf{I_{rms}=\frac{I_0}{\sqrt{2}}}}$

where $I_{rms}$ denotes root mean square value of alternating current.

$I_0$ denotes peak value of alternating current.

now, $I_{rms}=\frac{I_0}{\sqrt{2}}$

or, $\frac{I_{rms}}{I_0}=\frac{1}{\sqrt{2}}$

hence, The ratio of peak value and r.m.s value of an alternating current is 1/√2