Question

The ratio of present age of A,B&C is 3:1:2.If the product of their age is 162years than what will be C's age after 4 years

Answer 1

Heya ✋

Let see your answer !!!

Let the present age of A , B and C be 3x , x and 2x years. Then,

according to question ,

3x × x × 2x = 162

=> 6x^3 = 162

=> x^3 = 162/6

=> x^3 = 27

=> x = 3√27

=> x = 3

Hence , A's present age = 3 × 3 = 9 years

B's present age = 3 years

C's present age = 2 × 3 = 6 years.

C's age after 4 years = (6 + 4) years

= 10 years



Thanks :)))

Answer 2

Present age of A, B and C is 3:1:2
Product of their age is 162
Then, 162÷6=27
So, present age of A=27×3=81, B=27×1=27 and
C=27×2=54
Then, after four year the age of C=54+4=58