Math, asked by angadmonga6746, 11 months ago

The ratio of present age of anarchy and Alvaro's 6:7.Five years ago sum of their ages wad75. Find their present age.

Answers

Answered by aurumandargentum
3
let the age be X
Anarchy=6x
Alvaro =7x
sum of ages five years ago =75
=(6x-5)+(7x-5)=75
=13x-(-10)=75
=13x+10=75
13x=75-10
13x=65
x=65÷13=5
anarchy=6×5=30
alvaro=7×5=35
Answered by SmãrtyMohït
16
Here is your solution 

Given :-

Ratio of the present age of anarchy and Alvaro's is 6:7

5 year ago it becomes sum of ages 75

present age of anarchy and Alvaro's is 6x and 7x

A/q

=>(6x-5)+(7x-5)​=75
=>13x-10=75
=>13x=65
=>x=5

Hence

present age of anarchy =6x=6×5=30years 

present age of Alvaro's=7x=7×5=35years 

Hope it helps you
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