The ratio of present age of anarchy and Alvaro's 6:7.Five years ago sum of their ages wad75. Find their present age.
Answers
Answered by
3
let the age be X
Anarchy=6x
Alvaro =7x
sum of ages five years ago =75
=(6x-5)+(7x-5)=75
=13x-(-10)=75
=13x+10=75
13x=75-10
13x=65
x=65÷13=5
anarchy=6×5=30
alvaro=7×5=35
Anarchy=6x
Alvaro =7x
sum of ages five years ago =75
=(6x-5)+(7x-5)=75
=13x-(-10)=75
=13x+10=75
13x=75-10
13x=65
x=65÷13=5
anarchy=6×5=30
alvaro=7×5=35
Answered by
16
Here is your solution
Given :-
Ratio of the present age of anarchy and Alvaro's is 6:7
5 year ago it becomes sum of ages 75
present age of anarchy and Alvaro's is 6x and 7x
A/q
=>(6x-5)+(7x-5)=75
=>13x-10=75
=>13x=65
=>x=5
Hence
present age of anarchy =6x=6×5=30years
present age of Alvaro's=7x=7×5=35years
Hope it helps you
Given :-
Ratio of the present age of anarchy and Alvaro's is 6:7
5 year ago it becomes sum of ages 75
present age of anarchy and Alvaro's is 6x and 7x
A/q
=>(6x-5)+(7x-5)=75
=>13x-10=75
=>13x=65
=>x=5
Hence
present age of anarchy =6x=6×5=30years
present age of Alvaro's=7x=7×5=35years
Hope it helps you
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