Math, asked by AaryDubey, 9 months ago

the ratio of present age of monu and sonu is 5:8 .Eleven years ago the ratio of their age was 8:15. find their present age

Answers

Answered by swarnadeepmaiti
3

Step-by-step explanation:

ratio of present age of monu and sonu is 5:8

monu = 5x years

sonu = 8x. years [x is a constant ]

11 years ago, age of monu 5x - 11 years

age of sonu 8x - 11 years

Eleven years ago the ratio of their age was 8:15

so

 \frac{(5x - 11)}{(8x - 11)}  =  \frac{8}{15}

so, 75x - 165 = 64x - 88

75x - 64x = 165 - 88

11x = 77

x = 7

please follow.

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