Question

the ratio of present ages of a,b and c is 3,4,5. ten years ago the sum of their ages was 54 years what is the percent age of b​

Answer 1

Answer:

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Answer 2

Ratio

Given:

The ratio of present age of a, b, c is 3:4:5.

The sum of their ages 10 years ago, is 54 years.

To Find:

Percentage of b's age.

Explanation:

Let the present age of a is 3x.

And the present age of b is 4x.

and the present age of c is 5x.

According to question,

Ten years ago,

$3x+4x+5x=54\\\implies 12x=54\\\\\implies x=\frac{54}{12}\\\\\implies x=\frac{9}{2} \\\\x=4.5 \ years$

hence, age of a is 3x $=3\times 4.5=13.5 \ years$

Hence age of b is 4x=$4 \times 4.5=18 \ years$

Hence, age of c is 5x$=5 \times 4.5=22.5 \ years$

Percentage of b's age with total age=$\frac{18}{54} \times100=33.33\%$

Hence , percentage required is 33%.